2z^2+9z+7=0

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Solution for 2z^2+9z+7=0 equation: 



2z^2+9z+7=0

a = 2; b = 9; c = +7;
Δ = b2-4ac
Δ = 92-4·2·7
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-5}{2*2}=\frac{-14}{4}
=-3+1/2
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+5}{2*2}=\frac{-4}{4}
=-1
$

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